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Heat and Thermodynamics

Heat and Thermodynamics

Heat and Thermodynamics

A complete physics website covering heat, temperature, thermal expansion, calorimetry, transfer of heat, gas laws, thermodynamics, laws of thermodynamics, heat engines, refrigerators, diagrams, formulas, solved examples, and exercises.

1. Heat

Heat is a form of energy that flows from a hotter body to a colder body.

Hot Body
→
Transfer of Heat
→
Cold Body
Heat Energy (Q) = mcΔT
Hot Cold Heat Flow

2. Temperature

Temperature measures the degree of hotness or coldness of a body.

K = °C + 273
ScaleUnit
Celsius°C
KelvinK
Fahrenheit°F

3. Thermal Expansion

Most substances expand on heating and contract on cooling.

Cold Heated

Types of Expansion

  • Linear Expansion
  • Area Expansion
  • Volume Expansion

4. Transfer of Heat

Methods of Heat Transfer

MethodDescription
ConductionHeat transfer without movement of particles
ConvectionHeat transfer through movement of fluid
RadiationHeat transfer without medium
Conduction
•
Convection
•
Radiation

5. Calorimetry

Calorimetry is the measurement of heat exchanged.

Heat Lost = Heat Gained

Example

Find heat required to raise temperature of 2 kg water by 10°C.

Given:

m = 2 kg

c = 4200 J/kg°C

ΔT = 10°C

Q = mcΔT

Q = 2 × 4200 × 10

Q = 84000 J

6. Thermodynamics

Thermodynamics deals with relation between heat and mechanical energy.

First Law of Thermodynamics

ΔQ = ΔU + W

Heat supplied = Increase in internal energy + Work done.

Second Law of Thermodynamics

Heat cannot flow naturally from cold body to hot body.

7. Heat Engine and Refrigerator

Heat Engine

A heat engine converts heat energy into mechanical work.

Source Engine Sink

Refrigerator

A refrigerator transfers heat from low temperature to high temperature using external work.

8. Practice Exercises

Short Questions

  1. Define heat.
  2. What is temperature?
  3. Name methods of heat transfer.
  4. State first law of thermodynamics.
  5. What is calorimetry?

Numerical Problems

  1. Find heat needed to raise temperature of 5 kg water by 20°C.
  2. Convert 27°C into Kelvin.
  3. Calculate heat if m = 3 kg, c = 4200 J/kg°C and ΔT = 5°C.

9. Formula Summary

TopicFormula
Heat EnergyQ = mcΔT
Kelvin ConversionK = °C + 273
First LawΔQ = ΔU + W

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